Gradient and curl, can i move this derivative term out?

rasmusthsdr

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Jan 8, 2021
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Hi everyone

I have this problem that i simply can't figure out if i am allowed to do the following. I have represented it both in terms of the curl function and also of the gradient operator:
B is a vector field

[MATH]curl\left(-\frac{∂B}{∂t}\right)=-\frac{∂}{∂t} \left(curl\left(B\right)\right)[/MATH]
and

[MATH]\nabla\times \left(-\frac{∂B}{∂t}\right)=-\frac{∂}{∂t} \left(\nabla\times B\right)[/MATH]
Am i allowed to move that part out?

Best regards
Rasmus
 
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