The angles of elevation of a tower H meter high from points A and B are α and β respectively. An airplane is flying at a height greater than that of the tower and is descending towards the tower. If the angle of elevation of the airplane from point B is θ and the speed of the airplane is 500km/hr.
Prove that
Time taken for impact of the airplane and the tower is
H2 [tanθ (tanα + tanβ) – (tanαtanβ) + tan2β] / 500 tan2α tan2β
Prove that
Time taken for impact of the airplane and the tower is
H2 [tanθ (tanα + tanβ) – (tanαtanβ) + tan2β] / 500 tan2α tan2β