help to solve this differentail equation

[tinyjooker]

Hi Guys i am new between we <<



i need help to solve this differentail equation :

cos^2 x sinx d' =cos^3x.y+1


i tried many times to solve this question but i could not

so please help me to solve question
​

 

[HallsofIvy]

Hi Guys i am new between we <<



i need help to solve this differentail equation :

cos^2 x sinx d' =cos^3x.y+1


i tried many times to solve this question but i could not

so please help me to solve question
​

You have \(\displaystyle cos^2x sin xd'= cos^3xy+1\)

What is d'? Do you mean y'? And is that "\(\displaystyle cos^3xy\)" supposed to be \(\displaystyle cos^3(y)x\) or \(\displaystyle cos^3(xy)\)?

What have you tried many times so that we don't go over the same thing?

 

[mmm4444bot]

cos^2 x sinx d' =cos^3x.y+1

tried many times to solve this

Hello tinyjooker:

I cannot resolve your typing. Please retype the differential equation and use parentheses around the inputs to the trigonometric functions.

It is better to show multiplication with an asterisk, instead of a decimal point.

What is the meaning of d' in your equation?

Also, please show us one of your attempts.

Here is a link to the summary page of the forum guidelines.

Thank you :cool: