(ax+aw+bx+bw) ( x-w) ------------------ * ---------- (x^2 -w^2 ) ( a^2-b^2) would my answer be 1/a-b
N nae New member Joined Jun 18, 2006 Messages 33 Jul 29, 2006 #1 (ax+aw+bx+bw) ( x-w) ------------------ * ---------- (x^2 -w^2 ) ( a^2-b^2) would my answer be 1/a-b
pka Elite Member Joined Jan 29, 2005 Messages 11,990 Jul 29, 2006 #2 \(\displaystyle \L \frac{{ax + aw + bx + bw}}{{x^2 - w^2 }}\frac{{x - w}}{{a^2 - b^2 }} = \frac{{\left( {a + b} \right)\left( {x + w} \right)}}{{\left( {x + w} \right)\left( {x - w} \right)}}\frac{{\left( {x - w} \right)}}{{\left( {a - b} \right)\left( {a + b} \right)}}\)
\(\displaystyle \L \frac{{ax + aw + bx + bw}}{{x^2 - w^2 }}\frac{{x - w}}{{a^2 - b^2 }} = \frac{{\left( {a + b} \right)\left( {x + w} \right)}}{{\left( {x + w} \right)\left( {x - w} \right)}}\frac{{\left( {x - w} \right)}}{{\left( {a - b} \right)\left( {a + b} \right)}}\)