Help with solving tasks: (ctg a + tg a)/(1 + tg a) * cos a = 3/5
- Thread starter Vaki
- Start date
1.\(\displaystyle \dfrac{ctg(\alpha)+tg(\alpha)}{1+tg(\alpha)}\) cos@ is 3/5
2.I dont know where to put this so i will here A:B=4:5 B:C=3:2 C=4:7 How much is A:B:C
First off, I'm not familiar with the notation you've used here, but I'll assume that by ctg you mean "cotangent" and by tg you mean "tangent." If these assumptions are not correct, please reply with any necessary information about what they do mean.
For the first problem, you began by drawing a diagram featuring a right triangle and labeled one of its unknown angles alpha. You then used the mnemonic SOHCAHTOA to find two of the three sides and used the Pythagorean Theoremhttps://www.mathsisfun.com/pythagoras.html to find the last side... and then what?
For the second problem, you set up three equations from the ratios given: \(\displaystyle \dfrac{A}{B}=\dfrac{4}{5}\), \(\displaystyle \dfrac{B}{C}=\dfrac{3}{2}\), and \(\displaystyle \dfrac{C}{D}=\dfrac{4}{7}\), and solved the first for B in terms of A... and then what?
Please comply with the rules as laid out the read Read Before Postinghttps://www.freemathhelp.com/forum/threads/41537-Read-Before-Posting!! thread that's stickied at the too of every subforum, and share with us all of the work you've done on these problems, even the parts you know for sure are wrong. Thank you.