I am soo lost on this problem

[Eva Barragan]

Its a word problem i hate these!
the problem is: THE HEIGHT OF THE OBJECT AFTER BEING THROWN CAN BE MODELED BY THE EQUATION h=-5t^2+35t, WHERE h IS THE HEIGHT ABOVE THE GROUND IN METERS AND t IS THE TIME IN SECONDS.
AT WHAT TIMES WOULD THE OBJECT BE LOCATED AT 60meters ABOVE THE GROUND? SHOW YOUR WORK

 

[tkhunny]

Let's try this again:

h IS THE HEIGHT ABOVE THE GROUND IN METERS
...LOCATED AT 60meters ABOVE THE GROUND?

t IS THE TIME IN SECONDS.
AT WHAT TIMES...

{think}{ponder}

 

[KP]

this could be easier if you did it on graph paper

 

[stapel]

this could be easier if you did it on graph paper

How so? The algebraic solution is much quicker.

Eliz.

 

[KP]

thats true.......

 

[Guest]

When the height is 60 m ,
h=-5t^2+35t
60 =5t^2+35t

now solve this equation for t

 

[Eva Barragan]

thanx the test was over before i could see these post but thats waht i ended up doing
oh and kp there was a part of the problem where i had to graph the times but i didnt know how
thanks alot


-always appreciate the help
eva

 

[zerodegrees]

you know, what comes up must come down........