I couldn't do this question at my maths test.. help?

L

Lexadis

New member
Joined
Mar 22, 2013
Messages
17
This was the question: Using the date given in the figure, find the value of \(\displaystyle A\hat{O}B\).
The pic was something like this:
U5tkrs5.png​
It was a part I question, just for 2 marks. So it must be pretty simple, but I couldn't think of a way to do it at all, however much I thought :confused: Any help? Thank you c:

NOTE: -- I don't have any work to show, because I just don't know how to find the value of \(\displaystyle A\hat{O}B\). But I have worked out that since \(\displaystyle OA=OB(radius)\) \(\displaystyle O\hat{A}B=O\hat{B}A\) (when 2 sides of a triangle are equal, their opposite angles are equal).
But for anybody's sake I just don't know whether that is needed right here, nor can't I guess the relation between the right angled and the angle.

Guidance would be greatly appreciated, thank you very much c:
 
Lexadis said:
This was the question: Using the date given in the figure, find the value of \(\displaystyle A\hat{O}B\).
The pic was something like this:It was a part I question, just for 2 marks. So it must be pretty simple, but I couldn't think of a way to do it at all, however much I thought :confused: Any help? Thank you c:

NOTE: -- I don't have any work to show, because I just don't know how to find the value of \(\displaystyle A\hat{O}B\). But I have worked out that since \(\displaystyle OA=OB(radius)\) \(\displaystyle O\hat{A}B=O\hat{B}A\) (when 2 sides of a triangle are equal, their opposite angles are equal).
But for anybody's sake I just don't know whether that is needed right here, nor can't I guess the relation between the right angled and the angle.

Guidance would be greatly appreciated, thank you very much c:
Click to expand...
You pretty much have to use trig functions to find the angle. The sine of half the angle is (AB/2)/R
 
If there were no other data given,

there is no unique answer.
 
You must log in or register to reply here.
Top