I need help please solving this equation

Geophysics 111

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Dec 27, 2019
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4
Greeting All,
Can you please help me in this problem. I need to solve for Ax. The equation is:
D=atan((sqrt(Ax*Ax+Ay*Ay)/Az))
I need Ax=..........
Can you please help me?
 
Start by taking the tangent of each side, then either square each side or multiply by Az.

Please show any work you have done, so we can help you move on from there.
 
Thanks.
What I got is
tan D*Az= sqrt(Ax*Ax+Ay*Ay)
Then
tan (D*Az)^2 = Ax*Ax +Ay*Ay
Ax*Ax=tan (D*Az) ^2 - Ay*Ay
Is this write? I want only Ax
 
Thanks.
What I got is
tan D*Az= sqrt(Ax*Ax+Ay*Ay)
Then
tan (D*Az)^2 = Ax*Ax +Ay*Ay
Ax*Ax=tan (D*Az) ^2 - Ay*Ay ............................ Correct
Is this write? I want only Ax
You have only Ax on the left-hand-side of the equation!
 
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Correct except that you put D inside the parentheses, which is wrong.

You should have said this:

D = atan(sqrt(Ax*Ax+Ay*Ay)/Az)​
tan(D) = sqrt(Ax*Ax+Ay*Ay)/Az​
Az*tan(D) = sqrt(Ax*Ax+Ay*Ay)​
(Az*tan(D))^2 = Ax*Ax+Ay*Ay​
(Az*tan(D))^2-Ay*Ay = Ax*Ax​

So the result is Ax = sqrt((Az*tan(D))^2 - Ay*Ay).
 
Correct except that you put D inside the parentheses, which is wrong.

You should have said this:

D = atan(sqrt(Ax*Ax+Ay*Ay)/Az)​
tan(D) = sqrt(Ax*Ax+Ay*Ay)/Az​
Az*tan(D) = sqrt(Ax*Ax+Ay*Ay)​
(Az*tan(D))^2 = Ax*Ax+Ay*Ay​
(Az*tan(D))^2-Ay*Ay = Ax*Ax​

So the result is Ax = sqrt((Az*tan(D))^2 - Ay*Ay).
Thanks a lot
 
Thanks.
What I got is
tan D*Az= sqrt(Ax*Ax+Ay*Ay)
Then
tan (D*Az)^2 = Ax*Ax +Ay*Ay
Ax*Ax=tan (D*Az) ^2 - Ay*Ay
Is this write? I want only Ax
No, it is not correct.
Note that tan(r)*s \(\displaystyle \neq\)tan(rs). That is tan D*Az \(\displaystyle \neq\)tan (D*Az).
Also if you want to square tan (D*Az) you do not get tan[(D*Az)2], rather you get [tan(D*Az)]2 more commonly written as tan2(D*Az)

Also your answer must be wrong since you solved for Ax*Ax when you wanted to solve for Ax!
 
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