Hello. I was told that |e^(3in)|^2 is equal to 1. Can someone please explain why that is?
J johnbobson New member Joined May 6, 2013 Messages 7 May 6, 2013 #1 Hello. I was told that |e^(3in)|^2 is equal to 1. Can someone please explain why that is?
D Deleted member 4993 Guest May 6, 2013 #2 johnbobson said: Hello. I was told that |e^(3in)|^2 is equal to 1. Can someone please explain why that is? Click to expand... You should know: \(\displaystyle e^{i\theta} \ = \ cos(\theta) + i * sin(\theta)\) then: \(\displaystyle e^{i\pi} \ = ?? \) and \(\displaystyle [e^{i\pi}]^3 \ = \ e^{i3\pi} \ = ?? \) and \(\displaystyle [e^{i3\pi}]^2 \ = ?? \) Last edited by a moderator: May 7, 2013
johnbobson said: Hello. I was told that |e^(3in)|^2 is equal to 1. Can someone please explain why that is? Click to expand... You should know: \(\displaystyle e^{i\theta} \ = \ cos(\theta) + i * sin(\theta)\) then: \(\displaystyle e^{i\pi} \ = ?? \) and \(\displaystyle [e^{i\pi}]^3 \ = \ e^{i3\pi} \ = ?? \) and \(\displaystyle [e^{i3\pi}]^2 \ = ?? \)
