Integral Calculus
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Harry_the_cat
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Would you know how to find the area bounded by the vertical line x=2, x=9, the x-axis and the line g(x)?
D
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Let us calculate the area of "vertical" rectangle, of width = dx, at a distance x from the origin, and bounded by the curves f(x) and g(x).
The width of the rectangle is = dx
height of the rectangle = g(x) - f(x)
Area of the rectangle = [g(x)-f(x)] dx
Now what.......
Please show us what you have tried and exactly where you are stuck.
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Determining logarithmic function of the form f(x) = k ln(ax+b)
Not sure how to determine the values of a and b in the logarithmic function of the form f(x) = k ln(ax+b) from the given graph in the attached image. Please help !!
www.freemathhelp.com
HallsofIvy
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If you are not taking a Calculus class where did you get this problem?
If you are taking a Calculus class then you should know that the area between the graph of y= f(x) and y= g(x), with f(x)> g(x), is \(\displaystyle \int f(x)- g(x) dx\).
Here the area is given by \(\displaystyle \int_2^9 [(0.1x+ 4)- (1- e^{x/6})]dx= \int_2^9 (0.1x+ 3+ e^{x/6}) dx\). Do you know how to do that integral?
If you are taking a Calculus class then you should know that the area between the graph of y= f(x) and y= g(x), with f(x)> g(x), is \(\displaystyle \int f(x)- g(x) dx\).
Here the area is given by \(\displaystyle \int_2^9 [(0.1x+ 4)- (1- e^{x/6})]dx= \int_2^9 (0.1x+ 3+ e^{x/6}) dx\). Do you know how to do that integral?