I'm supposed to solve for x:
tanX + 2cosX = secX
I started by moving 2cosX to the other side, then squaring both sides:
tan2X = sec2X - 4 + 4 cos2X
Then I turned tan2X into sec2X - 1 and cancelled out the two sec2X's:
-1 = -4 + 4cos2X
Which turned into 3/4 = cos2X
And then cosX = +-(√3)/2
From here I figured X would be π/6 + 2πn, 5π/6 + 2πn, 7π/6 + 2πn, 11π/6 + 2πn, but my book's answer only has the last two of these, which doesn't make any sense to me.
tanX + 2cosX = secX
I started by moving 2cosX to the other side, then squaring both sides:
tan2X = sec2X - 4 + 4 cos2X
Then I turned tan2X into sec2X - 1 and cancelled out the two sec2X's:
-1 = -4 + 4cos2X
Which turned into 3/4 = cos2X
And then cosX = +-(√3)/2
From here I figured X would be π/6 + 2πn, 5π/6 + 2πn, 7π/6 + 2πn, 11π/6 + 2πn, but my book's answer only has the last two of these, which doesn't make any sense to me.