keep getting wrong answer

cotfw

New member
Joined
Sep 29, 2014
Messages
30
I'm supposed to solve for x:

tanX + 2cosX = secX

I started by moving 2cosX to the other side, then squaring both sides:

tan2X = sec2X - 4 + 4 cos2X

Then I turned tan2X into sec2X - 1 and cancelled out the two sec2X's:

-1 = -4 + 4cos2X

Which turned into 3/4 = cos2X

And then cosX = +-(√3)/2

From here I figured X would be π/6 + 2πn, 5π/6 + 2πn, 7π/6 + 2πn, 11π/6 + 2πn, but my book's answer only has the last two of these, which doesn't make any sense to me.
 
I'm supposed to solve for x:

tanX + 2cosX = secX

I started by moving 2cosX to the other side, then squaring both sides:

tan2X = sec2X - 4 + 4 cos2X

Then I turned tan2X into sec2X - 1 and cancelled out the two sec2X's:

-1 = -4 + 4cos2X

Which turned into 3/4 = cos2X

And then cosX = +-(√3)/2

From here I figured X would be π/6 + 2πn, 5π/6 + 2πn, 7π/6 + 2πn, 11π/6 + 2πn, but my book's answer only has the last two of these, which doesn't make any sense to me.
Since you used "square" operation, extraneous answers have crept in. So you need to find, out of the four solutions, which do satisfy the given (original) equation.
 
Top