Law of Sines: Solving for the triangle

[hollerback1]

Hi, school started for me again and I have my first test tommorow.

Here is the problem...

solve the triangle:
a = 12, b = 5, angleB = 20degrees

I found that angleA = 55.2 degrees,side c = 14.1 and angleC = 104.8degrees by using the law of sines. But, how do you find out if there is a need for a second angle and side for another triangle?

plz respond as soon as possible thank you.

 

[hollerback1]

hmmm....please respond before i go to sleep, which is about...8:45 pm Eastern time.

I'll be waiting/studying

Thanks.

 

[tkhunny]

This is not a chat service. If you want it NOW, you'll have to find a paying service. These free ones run on volunteers' schedules, not yours.

There is a test for that. If that angle 'C' is 90º, what is 'a'? That will explain it.

 

[hollerback1]

I'm sorry for asking for results NOW, I was just worried about my test tommorow. I apologize and will be patient from now on.

 

[tkhunny]

Did you figure out the perpendicular test?

Calculate that length.

If the other side is shorter, there are no solutions.
If the other side is longer, there may be two solutions.