In the following image, is the angle between the member CD and BE 60º? I'm really rusty on geometry.
R rooney New member Joined Feb 9, 2008 Messages 25 Mar 25, 2008 #1 In the following image, is the angle between the member CD and BE 60º? I'm really rusty on geometry.
L Loren Senior Member Joined Aug 28, 2007 Messages 1,299 Mar 25, 2008 #2 Re: Line Intersections Yes. Opposite angles of a parallelogram are equal.
R rooney New member Joined Feb 9, 2008 Messages 25 Mar 25, 2008 #3 Re: Line Intersections Thanks very much.
D Deleted member 4993 Guest Mar 29, 2008 #4 rooney said: In the following image, is the angle between the member CD and BE 60º? I'm really rusty on geometry. Click to expand... CDB = 60[sup:3gotdsm6]o[/sup:3gotdsm6] CDE = 120[sup:3gotdsm6]o[/sup:3gotdsm6]
rooney said: In the following image, is the angle between the member CD and BE 60º? I'm really rusty on geometry. Click to expand... CDB = 60[sup:3gotdsm6]o[/sup:3gotdsm6] CDE = 120[sup:3gotdsm6]o[/sup:3gotdsm6]