Looking for the steps to solving this L{u( t − 2)e^(3 t)}?

[qwerty123z]

looking for the steps to solving this L{u( t − 2)e^(3 t)}. The problem itself looks like a second shifting theorem problem but i don't know how it's done.

answer was given as:

((e^6)(e^-2s))/(s-3)

 

[Deleted member 4993]

looking for the steps to solving this L{u( t − 2)e^(3 t)}. The problem itself looks like a second shifting theorem problem but i don't know how it's done.

answer was given as:

((e^6)(e^-2s))/(s-3)

Substitute:

t₁ = t-2

L{u( t − 2)e^(3 t)} → L{u( t₁)e^(3 t₁ + 6)} → e⁶ * L{u(t₁)e^(3 t₁)}