majorly struggling with this bad boy!!

bobbybobster

New member
Joined
Nov 8, 2013
Messages
1
Three impedances are connected in parallel, Z1= 2+2j, Z2 = 1+j5, and Z3 = j6. Find the equivalent admittance Y.

where: Y= 1/Z1 + 1/Z2 + 1/Z3

Express the admittance in both rectangular and polar forms.


any help would be majorly appreciated with this...
 
Three impedances are connected in parallel, Z1= 2+2j, Z2 = 1+j5, and Z3 = j6. Find the equivalent admittance Y.

where: Y= 1/Z1 + 1/Z2 + 1/Z3

Express the admittance in both rectangular and polar forms.
Are the numbers which follow the letters meant to be exponents? Does "j" stand for the square root of negative one?

How far have you gotten in plugging the given values into the given formula, and simplifying? Where are you stuck?

Please be complete. Thank you! ;)
 
Three impedances are connected in parallel, Z1= 2+2j, Z2 = 1+j5, and Z3 = j6. Find the equivalent admittance Y.

where: Y= 1/Z1 + 1/Z2 + 1/Z3

Express the admittance in both rectangular and polar forms.


any help would be majorly appreciated with this...
Each admittance should be rationalized by multiplying numerator and denominator by the complex conjugate.

\(\displaystyle Y_1 = \dfrac{Z_1^*}{Z_1\times Z_1^*} = \dfrac{2 - 2j}{4+4} = \dfrac 14(1 - j)\)

When you have rationalized all three, they add as complex numbers (in rectangular form).
 
Top