Natural Log Problem: convert e^(10^23) in the form 10^x,

[charlieko]

Is there anyway to convert e^(10^23) in the form 10^x, for some x?

It is one of problems in my physics textbook that I have to do for homework, so I know it is possible...
But I tried to do it by setting y=e^(10^23) and somehow solve for y as 10^x, but I have failed many times.
Can anyone have an idea?

 

[o_O]

Re: Natural Logarithm Problem

So you want to express \(\displaystyle e^{10^{23}}\) in the form of \(\displaystyle 10^{x}\)?

Well, you can set them equal to each other and solve for x:

\(\displaystyle 10^{x} = e^{10^{23}}\)

\(\displaystyle ln10^{x} = lne^{10^{23}}\)

etc. etc.