Need help calculating - range of speeds for cosmic rays

Leotardo

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Hello all... if anyone can help I am trying to determine the speed of cosmic ray particles in meters per second - I am mainly looking for the highest speeds they attain but I would like to know the range of speeds they travel at and how you calculate this.

I am terrible with math though so please bear with me.
 
Hello all... if anyone can help I am trying to determine the speed of cosmic ray particles in meters per second - I am mainly looking for the highest speeds they attain but I would like to know the range of speeds they travel at and how you calculate this.

I am terrible with math though so please bear with me.

Then why are you tackling this problem??

If you are getting into particle physics, without being good at math, it is like diving into middle of Pacific Ocean when you are terrible with swimming.
 
I don't see that this has anything to do with mathematics! You "determine the speed of cosmic ray particles" by measuring them! So what kind of measuring equipment do you have? Are you measuring near the surface of the earth or high in the atmosphere?
 
Then why are you tackling this problem??

If you are getting into particle physics, without being good at math, it is like diving into middle of Pacific Ocean when you are terrible with swimming.


I know it doesn't seem to make sense... but this is the situation I am in none the less.. haha I wish I could explain this more now. I can later when I have written it out.


The problem I have is that the speed of cosmic rays seem to be written out in energies rather than meters per second.

I need to convert the energies into meter per second.

Here is the highest energy -

3×1020 eV


The first observation of a cosmic ray particle with an energy exceeding 1.0×1020 eV (16 J) was made by Dr John D Linsley and Livio Scarsi at the Volcano Ranch experiment in New Mexico in 1962.[4][5]Cosmic ray particles with even higher energies have since been observed. Among them was the Oh-My-God particle observed on the evening of 15 October 1991 over Dugway Proving Ground, Utah. Its observation was a shock to astrophysicists, who estimated its energy to be approximately 3×1020 eV(50 J)[6]—in other words, a subatomic particle with kinetic energy equal to that of a baseball (5 ounces or 142 grams) traveling at about 100 kilometers per hour (60 mph). It was most likely a proton traveling very close to the speed of light, slower by only about 1.5 femtometers (quadrillionths of a meter) per second, or about 0.9999999999999999999999951c, based on its observed energy. At that speed, in a year-long race between light and the particle, the particle would fall behind only 46 nanometers, or 0.15 femtoseconds (1.5×10−16 s).[7]
The energy of this particle is some 40 million times that of the highest energy protons that have been produced in any terrestrial particle accelerator. However, only a small fraction of this energy would be available for an interaction with a proton or neutron on Earth, with most of the energy remaining in the form of kinetic energy of the products of the interaction.[citation needed] The effective energy available for such a collision is the square root of double the product of the particle's energy and the mass energy of the proton, which for this particle gives 7.5×1014 eV, roughly 50 times the collision energy of the Large Hadron Collider.[citation needed]
 
I know it doesn't seem to make sense... but this is the situation I am in none the less.. haha I wish I could explain this more now. I can later when I have written it out.


The problem I have is that the speed of cosmic rays seem to be written out in energies rather than meters per second.

I need to convert the energies into meter per second.

Here is the highest energy -

3×1020 eV

Since you cannot tell us - we cannot tell you!!

Anyway, if you had carefully read your "reference" - you should get a pretty good hint about calculating it from the energy.
 
I can tell you... but it's going to take a long long time.

I had an idea of how to do the calculation but I need to know that it is precise... It probably seems obvious to you but again.. I am terrible with math.
 
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