Please help me solve this...

[Vijayram]

Hi I'm sending this question again as I said "Circle" instead of "Triangle" in the one section, sorry: This is what it should read:
Given Right Angle Triangle DBC where C= 90 degrees, B=63,43 degrees, and D=26.57 degrees. Length of CD=32, Length of CB=16 and the hypotenuse=DB=35.8. If a line is drawn from B into the triangle and stops at point E, such that it forms Triangle EFB, where EF intersects CB at point F, what is the value of EF, EB and the angle at which B is split by EB? (note: Assume that EB does not become the radius of the incircle of Triangle DCB as E is at any point in the triangle DCB. Also, Assume that EB does not split angle b into 2 equal halves) Please help, I have to have this answer urgently.

 

[galactus]

Per the diagram, is this what you mean:

 

[Denis]

Hi I'm sending this question again...

If you're sending "again", why is your number of posts = 1 ? :shock:

 

[galactus]

Because the redundant one has been deleted.

 

[mmm4444bot]

a line is drawn from B into the triangle and stops at point E, such that it forms Triangle EFB, where EF intersects CB at point F

note: … E is at any point in the triangle DCB

I highlighted some key words in red.

I read this text to mean that point E can be located anywhere within the interior of triangle DBC and point F can be located anywhere between the endpoints of CB.

This means that there are an infinite number of possible triangles EFB.

If this is the case, then you will need to introduce some symbolic expressions to represent the location of points E and F, and report the requested distances in terms of the symbols.

Please confirm for us that you have typed the given information verbatim. Apparently, you have no diagram, so we have to proceed using the exact words only.

 

[Vijayram]

Hi Thanks for the Reply, EB does not intersect on cd as you hav indicated. and EF is a perpendiculat line. So, point EB lies somewhere in the Triangle given. Hope this clarifies

 

[mmm4444bot]

EF is a [perpendicular] line

point EB lies somewhere in the Triangle given

It now seems that EF is perpendicular to BC.

"EB" (above) is a typo, yes?

Clearly, you did not previously share all of the information that came with this exercise. Do we now have all of the given information?

 

[galactus]

V, try making a diagram in Paint and posting it on the site.

Make up a Paint drawing and use Upload Attachment on this site to post the drawing.