hi friends .... sorry if this is a very elementary question.
In bernoulli equation we have:
1 – y’+p(x)y=g(x)y
2 – (dy/y)+[p(x)-g(x)]dx=0
3 - ln y = integral {[g(x)-p(x)]dx }
4 – y=c * Exp(integral{ [g(x)-p(x)]dx )}
A) I want to know how 3th line derive to 4th line? b) Why c Multiple by exp?
thanks
In bernoulli equation we have:
1 – y’+p(x)y=g(x)y
2 – (dy/y)+[p(x)-g(x)]dx=0
3 - ln y = integral {[g(x)-p(x)]dx }
4 – y=c * Exp(integral{ [g(x)-p(x)]dx )}
A) I want to know how 3th line derive to 4th line? b) Why c Multiple by exp?
thanks