Radius and center of circle

[Squexy]

Can someone show me how to resolve this question?

A particular circle in the standard (x,y) coordinate
plane has an equation of (x − 5)2 + y2 = 38. What are
the radius of the circle, in coordinate units, and the
coordinates of the center of the circle?
radius center
F. √38 ( 5,0)
G. 19 ( 5,0)
H. 38 ( 5,0)
J. √38 (−5,0)
K. 19 (−5,0)


The answer is F

 

[Ishuda]

This is just a matter of recognizing the standard equation for a circle which is
(x-x₀)² + (y-y₀)² = r²
where r is the radius and (x₀, y₀) is the center of the circle.

Now compare your equation
(x − 5)² + y² = 38
to that one

As a hint note that y = y - 0, and 38 = ( √38 )²

 

[Deleted member 4993]

Can someone show me how to resolve this question?

A particular circle in the standard (x,y) coordinate
plane has an equation of (x − 5)² + y² = 38. What are
the radius of the circle, in coordinate units, and the
coordinates of the center of the circle?
radius center
F. √38 ( 5,0)
G. 19 ( 5,0)
H. 38 ( 5,0)
J. √38 (−5,0)
K. 19 (−5,0)


The answer is F

The standard form of a circle of radius r and centered at (h,k) is:

(x - h)² + (y - k)² = r²