rearranging an expression involving arcsin

[km707]

hi, I'm supposed to show that by rearranging this expression, I should get x = x[sub:26h1c9jo]0[/sub:26h1c9jo]

sin[sup:26h1c9jo]-1[/sup:26h1c9jo](x/x[sub:26h1c9jo]0[/sub:26h1c9jo])[sup:26h1c9jo]1/2[/sup:26h1c9jo] - 1/2 sin[2sin[sup:26h1c9jo]-1[/sup:26h1c9jo](x/x[sub:26h1c9jo]0[/sub:26h1c9jo])[sup:26h1c9jo]1/2[/sup:26h1c9jo]] = pi/2

I don't even know if i've started it right..

i've substituted theta for sin[sup:26h1c9jo]-1[/sup:26h1c9jo](x/x[sub:26h1c9jo]0[/sub:26h1c9jo])[sup:26h1c9jo]1/2[/sup:26h1c9jo] so I've written the expression

theta - 1/2 sin(theta) = pi/2

..but I really don't know what I'm doing here!

thanks in advance!

 

[Deleted member 4993]

hi, I'm supposed to show that by rearranging this expression, I should get x = x[sub:2dy48zwm]0[/sub:2dy48zwm]

sin[sup:2dy48zwm]-1[/sup:2dy48zwm](x/x[sub:2dy48zwm]0[/sub:2dy48zwm])[sup:2dy48zwm]1/2[/sup:2dy48zwm] - 1/2 sin[2 sin[sup:2dy48zwm]-1[/sup:2dy48zwm](x/x[sub:2dy48zwm]0[/sub:2dy48zwm])[sup:2dy48zwm]1/2[/sup:2dy48zwm]] = pi/2

I don't even know if i've started it right..

i've substituted theta for sin[sup:2dy48zwm]-1[/sup:2dy48zwm](x/x[sub:2dy48zwm]0[/sub:2dy48zwm])[sup:2dy48zwm]1/2[/sup:2dy48zwm] so I've written the expression

theta - 1/2 sin(2theta) = pi/2

The problem just does not look right.

..but I really don't know what I'm doing here!

thanks in advance!