( sec^2(x) + csc^2(x) ) - ( tan^2(x) - cot^2(x) )

[Slipery]

Hey, I am just starting my trig identities unit and I have a question I'm stuck on.. it's probably very easy, so bear with me and don't make fun of me ^^

(sec²x + csc ²x) - (tan²x - cot²x)
So I have ( 1/cos²x+ 1/sin²x) - (sin²x/cos²x+ cos²x/sin²x)...

 

[pka]

Re: Quick and easy question trig identities

don't make fun of me
(sec²x + csc ²x) - (tan²x - cot²x)

This is not making fun. It is just a true statement.
That is not an identity. Identities have "equals to" somewhere in them.

 

[galactus]

Re: Quick and easy question trig identities

Exactly, what are you trying to do?.

Remember that:

\(\displaystyle cot^{2}(x)+1=csc^{2}(x)\)

and

\(\displaystyle csc^{2}(x)-1=cot^{2}(x)\)

and

\(\displaystyle sec^{2}(x)=tan^{2}(x)+1\)

These are identities you can use.

Also, more obscure, is \(\displaystyle sec^{2}(x)+csc^{2}(x)=\frac{-8}{cos(4x)-1}\)

Now, whatever you're doing, can you take it from there?.