Simplifing rational algebraic exp. with variable >0

[Maria13]

Hi you guys!

Trying to remember how this stuff works, check it out:

[(6x - 18) / (3x^2 + 2x - 8)] × [(12x - 16) / (4x - 12)]

I would appreciate your help!

 

[galactus]

\(\displaystyle \L\\\frac{6x-18}{3x^{2}+2x-8}\cdot\frac{12x-16}{4x-12}\)

Factor the respective numerators and denominators and cancel:

\(\displaystyle \L\\\frac{6(x-3)}{(3x-4)(x+2)}\cdot\frac{4(3x-4)}{4(x-3)}\)

I'll leave you finish. Okey-doke?.