Simplify(5y/axy^2 + 4b)/(bx@y)

[Matholdie]

\(\displaystyle \frac{5y/axy^2 + 4b}{bx@y}\)

I get \(\displaystyle \frac{5x+4a}{ax^2y}\)

Am I on the right path here?

Edit: Don't forget to include the slash before "frac". Enclose numerator and denominator separately. Again, I wasn't sure exactly what you meant, so I couldn't completely fix it. Another good try. You'll get it.

 

[Denis]

\(\displaystyle \frac{5y/axy^2 + 4b}{bx@y}\)

Still very unclear:
what does bx@y mean?
is 5y divided by axy^2 or by (axy^2 + 4b)?

Can you not ask someone to ACTUALLY show you how to post properly?