simplifying (X^2-9)/(x^2+x) divided by (3-x)/(x^2-1)

[iTRY]

hi. I need help simplifying:

(X^2-9)/(x^2+x) divided by (3-x)/(x^2-1)

I get the equation to simplify to ((x+3)(x+1)(x+1))/(x^2+x) ... but what do I do next?

 

[galactus]

Try factoring and cancelling.

\(\displaystyle \L\\\frac{(x^{2}-9)}{(x^{2}+x)}\cdot\frac{(x^{2}-1)}{(3-x)}\)

Factor the numerators and denominators, cancel. It'll reduce down. Be careful of the 3-x as opposed to x-3.

 

[Denis]

hi. I need help simplifying:
(X^2-9)/(x^2+x) divided by (3-x)/(x^2-1)
I get the equation to simplify to ((x+3)(x+1)(x+1))/(x^2+x) ... but what do I do next?

You're doing something wrong: the (x+1)'s should cancel out;
how did you get 'em both in the numerator?
AND: are you sure of (3-x)? Is that not (x-3)?