Simultaneous eqns: 4x(x^2+y^2-1)=0, 4y(x^2+y^2+1)=0

[devinaxx]

4x(x^2+y^2-1)=0
4y(x^2+y^2+1)=0
Simultaneous equation
(X,y)=(0,0) と(1,0), (-1,0)
Can someone give me hint to find x,y? Using substitution or elimination?


Sent from my iPhone using Tapatalk

 

[Deleted member 4993]

4x(x^2+y^2-1)=0
4y(x^2+y^2+1)=0
Simultaneous equation
(X,y)=(0,0) と(1,0), (-1,0)
Can someone give me hint to find x,y? Using substitution or elimination?


Sent from my iPhone using Tapatalk

You get three conditions:

x=0 and y=0, or,

x= 0 and x^2 + y^2 + 1 =0, or,

x^2 + y^2 - 1 = 0 and y = 0

 

[stapel]

4x(x^2+y^2-1)=0
4y(x^2+y^2+1)=0
Simultaneous equation
(X,y)=(0,0) と(1,0), (-1,0)

What is the meaning of the special character between the (0,0) and the (1,0)?

Can someone give me hint to find x,y? Using substitution or elimination?

How does this relate to the post-calculus topic of differential equations? (For instance, what topic in your diff-EQ text generated this exercise?)

When you reply, please include a clear listing of what you did with the hints for the basic algebra, provided earlier. Thank you!