sin, cos, tan, etc..

[sorceres13]

I need to find out the equivalent to sin x tan^2 x + sin x /tan x, for 0 < x < 90 degrees. I am trying to help my daughter with this but find that I need help first I am grateful for any assistance

 

[tkhunny]

sin x tan^2 x + sin x /tan x

It's begging to be transformed. tan(x) = sin(x)/cos(x)

That should get you started.

 

[Deleted member 4993]

I need to find out the equivalent to sin x tan^2 x + sin x /tan x, for 0 < x < 90 degrees. I am trying to help my daughter with this but find that I need help first I am grateful for any assistance

Is your problem:

\(\displaystyle sin(x) * tan^2(x) \ + \ \frac{sin(x)}{tan(x)}\) .............. This is what you have posted (equivalent)

or

\(\displaystyle \frac{sin(x) * tan^2(x) \ + \ sin(x)}{tan(x)}\)

If the second option is correct - then you should have used grouping symbols and PEMDAS and posted:

[sin(x) * tan^2(x) + sin(x)]/tan(x)