Slopes of Parallel and Perpendicular Lines

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Zanyah101

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I'm having trouble solving this problem, because of the fractions. I did most of it, it's just the end that confuses me. Can someone please tell me what to do next?
C(-4,8); y=4/9x+4
y-8=4/9(x-(-4))
y-8=4/9(x+4)
y-8=4/9x+?
 
Zanyah101 said:
I'm having trouble solving this problem, because of the fractions. I did most of it, it's just the end that confuses me. Can someone please tell me what to do next?
C(-4,8); y=4/9x+4
y-8=4/9(x-(-4))
y-8=4/9(x+4)
y-8=4/9x+?
Click to expand...
Thanks for showing work, as we ask; but you haven't stated the problem!

It looks as if you were asked to find the equation of the line through (-4, 8), parallel to y = 4/9 x + 4.

The next step is to distribute: you multiplied 4/9 times x; now you need to multiply 4/9 times 4. That means multiplying 4/9 times 4/1. Can you do that?

Then you'll have to add 8 to that; this means adding 8/1 and using a common denominator.

Please show whatever work you can attempt, so we can see where to help.
 
I completely apologize. The question was just as you guessed.
I did 4/9 times 4/1 and got 16/9. Then I did 16/9 plus 8/1 and got 24/10. After getting 24/10 I simplified it to 12/5.
And I got y=4/9x+12/5
 
You say you got \(\displaystyle \frac{16}{9}+\frac{8}{1}=\frac{24}{10}\).
Think about that for a second.
How could "something more than 1" + "8" give you "2 and a bit"?

When adding fractions, you do NOT simply add the tops and add the bottoms.
You need to get a common denominator.
\(\displaystyle \frac{16}{9}+\frac{8}{1}=\frac{16}{9} + \frac{72}{9}=\frac{88}{9}\)
 
So 1/2 + 1/2 = 2/4 = 1/2 (2/4 reduces to 1/2)

So if you eat half of a cake and go back later and eat the other half in the end you just ate 1/2 of the cake
 
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