Solve This Equation it's making me go crazzy

evilhero223

New member
Joined
Mar 19, 2017
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4
i've been attempting to solve this for like 3 hours now my head hurts. can someone solve this??

MCD_1220_Ass1_Tri1_17 (1)-page-001.jpg
 
Well for the first one, i used trig identity to sub and get 2-sin(x)=1+sin^2(x) but i dont know how to solve the rest

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Well for the first one, i used trig identity to sub and get 2-sin(x)=1+sin^2(x) but i dont know how to solve the rest

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2 - sin(x)=1+ 6 * sin^2(x)

6 * sin^2(x) + sin(x) -1 = 0

[3 * sin(x) - 1][2 * sin(x) +1] = 0

Above is a quadratic equation. Solve for sin(x)
 
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