1) solve using quadratic equation x^2 - 4x - 5 = 0 2) solve using quadratic formula x^2 - 4x - 5 = 0
L loretta195 New member Joined Nov 11, 2006 Messages 1 Nov 20, 2006 #1 1) solve using quadratic equation x^2 - 4x - 5 = 0 2) solve using quadratic formula x^2 - 4x - 5 = 0
skeeter Elite Member Joined Dec 15, 2005 Messages 3,216 Nov 20, 2006 #2 solve using quadratic equation ? x<sup>2</sup> - 4x - 5 = 0 (x - 5)(x + 1) = 0 using the quadratic formula ... a = 1, b = -4, c = -5 \(\displaystyle \L x = \frac{4 \pm \sqrt{(-4)^2 - 4(1)(-5)}}{2(1)}\)
solve using quadratic equation ? x<sup>2</sup> - 4x - 5 = 0 (x - 5)(x + 1) = 0 using the quadratic formula ... a = 1, b = -4, c = -5 \(\displaystyle \L x = \frac{4 \pm \sqrt{(-4)^2 - 4(1)(-5)}}{2(1)}\)
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,582 Nov 20, 2006 #3 loretta195 said: 1) solve using quadratic equation Click to expand... Were the instructions for this one perhaps something like "Solve the quadratic by factoring"...? Thank you. Eliz.
loretta195 said: 1) solve using quadratic equation Click to expand... Were the instructions for this one perhaps something like "Solve the quadratic by factoring"...? Thank you. Eliz.