Too much power(s): 4h^6 + b^2h^4 = 4V^2, b^6 + 4b^4h^2 = 64V^2

[ray5450]

Is there a way to solve this set for either b or h in terms of V? If so, I just need a hint, for now:

4h⁶ + b²h⁴ = 4V²

b⁶ + 4b⁴h² = 64V²

Thanks.

 

[ray5450]

I am not trying to solve for V, but only h or b in terms of V, but not h in terms of b or b in terms of h (the line where you solve has b in terms of h).

Like I implied, maybe it is not possible. (?)

Let "#" be a possible number(s), if any, unknown now, but not in the solution, and let "?", be an operation(s), if any, unknown now but not in the solution:

Something like b = # ? V^#
or
h = # ? V^#

Thanks.

 

[ray5450]

Okay, thanks. That is actually a helpful clue.