For each of the following pairs A, B of topological spaces determine whether they are homeomorphic. In each case, either display a momeomorphism or give a convincing reason why they cannot be homeomorphic.
Note:
R=means real numbers
Q=stands for rational numbers
Z=stands for integers numbers
R\Q stands for is in R but not in Q.
a. A is the open interval (0,1) and B= R( both with the usual topology).
b. A is the open interval (0,1) and B= [0,1] (both with the usual topology)
c. A=R and B=R^2 (both with the usual topology).
( hint: what happens if you delete a point x_0 from R?)
d. A=Z and B=Q, both as subspaces of R.
e.A= (R\Q) and B=Q, both as subspaces of R.
f. A=R with the usual topology and B={(x,y) is a member of R^2: xy=1, x>0} as a subspace of R^2.
Note:
R=means real numbers
Q=stands for rational numbers
Z=stands for integers numbers
R\Q stands for is in R but not in Q.
a. A is the open interval (0,1) and B= R( both with the usual topology).
b. A is the open interval (0,1) and B= [0,1] (both with the usual topology)
c. A=R and B=R^2 (both with the usual topology).
( hint: what happens if you delete a point x_0 from R?)
d. A=Z and B=Q, both as subspaces of R.
e.A= (R\Q) and B=Q, both as subspaces of R.
f. A=R with the usual topology and B={(x,y) is a member of R^2: xy=1, x>0} as a subspace of R^2.