Solve the equation in the interval [0,360)
2cos3theta = cos theta
So far I have:
2cos3theta-cos theta=0
2u3-u=0
u(2u2-1)=0
u=0 or u=1/2
so
cos theta=0 or cos theta= 1/2
theta= cos-11/2= 60 degrees, 300 degrees
Am I going in the right direction or do something wrong? Also I am stumped on how to get the 6 angles for the solution? I am stumped beyond this point...Help is appreciated!!
2cos3theta = cos theta
So far I have:
2cos3theta-cos theta=0
2u3-u=0
u(2u2-1)=0
u=0 or u=1/2
so
cos theta=0 or cos theta= 1/2
theta= cos-11/2= 60 degrees, 300 degrees
Am I going in the right direction or do something wrong? Also I am stumped on how to get the 6 angles for the solution? I am stumped beyond this point...Help is appreciated!!