Trigonometric Identities!!!

lukelowe

New member
Joined
May 27, 2011
Messages
7
So how about something a little different? Sec^2(theta) - Tan^2(theta) + Tan(theta) all over Sec(theta) = Sin(theta) + Cos(theta). I'm not sure which side to work with here or what Identities to use.
 
lukelowe said:
So how about something a little different? Sec^2(theta) - Tan^2(theta) + Tan(theta) all over Sec(theta) = Sin(theta) + Cos(theta). I'm not sure which side to work with here or what Identities to use.

Start a new post with a new thread.

Read the instructions posted in "Read before Posting" - show your work.

Start with Left-hand-side and use the identity:

\(\displaystyle sec^2(\theta) \ = \ 1 + tan^2(\theta)\)

Please share your work, indicating exactly where you are stuck - so that we may know where to begin to help you.
 
Subhotosh Khan said:
Please share your work, indicating exactly where you are stuck - so that we may know where to begin to help you.
Subhotosh, I got an extra red ink cartridge; wanna buy it?
Sell it to you half-price: only $167.50 :wink:
 
Denis said:
Subhotosh Khan said:
Please share your work, indicating exactly where you are stuck - so that we may know where to begin to help you.
Subhotosh, I got an extra red ink cartridge; wanna buy it?
Sell it to you half-price: only $167.50 :wink:

Nope ... I don't need to buy no stinkin' red ink .... I write with blood .... collected during ice-hockey-matches.....
 
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