The Question reads “Solve for x where 0≤x≤360 5sin(2x - 20) = 3” and I just don’t know how to do it?
K Kristine_Alexandra New member Joined Feb 22, 2021 Messages 1 Feb 22, 2021 #1 The Question reads “Solve for x where 0≤x≤360 5sin(2x - 20) = 3” and I just don’t know how to do it?
Steven G Elite Member Joined Dec 30, 2014 Messages 14,596 Feb 22, 2021 #2 I am sure that you can do something, Can you solve for sin(2x-20)?
J JeffM Elite Member Joined Sep 14, 2012 Messages 7,875 Feb 22, 2021 #3 Are you studying the arcsine function?