Trigonometry Help

WTF?

Junior Member
Joined
Sep 16, 2005
Messages
95
triangle55.jpg


Hello, I'm in need of a bit of a push here. How would I go about finding x ?

I'm aware of the trigonometry identities, so cosine would be suitable for this one, right?

I need help on how to set this sucker up,

so is it:
\(\displaystyle cos55=(11.5/X)\)

Then:
\(\displaystyle xCos55=11.5\)

Then:
\(\displaystyle xCos55/(Cos55) = 11.5/(Cos55)\) or do I need to divide by 55 and then multiply 11.5 by Cos^-1 (inverse cosine)
 
Top