Vectors Problem Regarding Heading

[FabZeros]

Hello all, I was learning about vectors today and can't seem to understand how to calculate the heading after getting the tangent of the angle.

for this question I got the right magnitude but a= tan^-1(-55.6/254.6) is around -12.3 degrees. Since I'm looking to the heading, I thought that I should add 90 degrees to it making a heading of 102.3 degrees... Sorry if I'm being confusing... But here is e problem.

number 43 is the specific one...

 

[FabZeros]

Problem number 43 sorry forgot to write that down.

 

[Quaid]

for this question I got the right magnitude but a= tan^-1(-55.6/254.6) is around -12.3 degrees.

number 43 is the specific one

Please show your work.

Did you calculate the components for both the plane vector and wind vector?

Cheers

PS: Here's a link to the forum guidelines summary.

 

[HallsofIvy]

"96 degrees heading" means the desired line of flight is at an angle of 96 degrees from due north. If you were to set up an xy- coordinate system such that positive y is north and positive x is right (pretty standard), the vector is 4 degrees below the positive x-axis. The wind, "from the South West at a heading of 37 degrees", is 37 degrees from the positive y-axis so 90- 37= 53 degrees above the x- axis. You want to find a vector that, added to the wid vector gives the desired line. That, in turn means that you want to find the vector that is the desired line minus the wind. You have a triangle such that one angle is 53+ 4= 57 degrees and the two adjacent sides of lengths 225 and 50.