Verifying Trig Identities

\(\displaystyle \frac{1}{1-sin(x)}+\frac{1}{1+sin(x)}\)

Cross multiply like you would when adding fractions, simplify, and it'll fall into place.
 
wouldn't that end up cancelling out the sin x? or do those two terms on the left also equal the 2 sec^2 x?
 
If you cross multiply:

\(\displaystyle \frac{1+sin(x)+1-sin(x)}{(1-sin(x))(1+sin(x))}\)

Yes, the sin's in the numerator cancel and you can then see why it is \(\displaystyle 2sec^{2}(x)\)
 
alright. thank you very much. do you happen to understand how to do my other posts? i am pretty desperate haha
 
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