Verfify the following trig idenity: 1/(1-sin?) + 1/(1+sin?) = 2sec^2?
B bobbyflay21 New member Joined Dec 11, 2010 Messages 11 Dec 11, 2010 #1 Verfify the following trig idenity: 1/(1-sin?) + 1/(1+sin?) = 2sec^2?
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,216 Dec 11, 2010 #2 \(\displaystyle \frac{1}{1-sin(x)}+\frac{1}{1+sin(x)}\) Cross multiply like you would when adding fractions, simplify, and it'll fall into place.
\(\displaystyle \frac{1}{1-sin(x)}+\frac{1}{1+sin(x)}\) Cross multiply like you would when adding fractions, simplify, and it'll fall into place.
B bobbyflay21 New member Joined Dec 11, 2010 Messages 11 Dec 11, 2010 #3 wouldn't that end up cancelling out the sin x? or do those two terms on the left also equal the 2 sec^2 x?
wouldn't that end up cancelling out the sin x? or do those two terms on the left also equal the 2 sec^2 x?
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,216 Dec 11, 2010 #4 If you cross multiply: \(\displaystyle \frac{1+sin(x)+1-sin(x)}{(1-sin(x))(1+sin(x))}\) Yes, the sin's in the numerator cancel and you can then see why it is \(\displaystyle 2sec^{2}(x)\)
If you cross multiply: \(\displaystyle \frac{1+sin(x)+1-sin(x)}{(1-sin(x))(1+sin(x))}\) Yes, the sin's in the numerator cancel and you can then see why it is \(\displaystyle 2sec^{2}(x)\)
B bobbyflay21 New member Joined Dec 11, 2010 Messages 11 Dec 11, 2010 #5 alright. thank you very much. do you happen to understand how to do my other posts? i am pretty desperate haha
alright. thank you very much. do you happen to understand how to do my other posts? i am pretty desperate haha