x^2+(2k+1) x+(k^2+k+1) =0

[maths_arghh234]

show that the equation (the subject title )
has no real roots whatever the value of k

i'm not even sure where to start !! plleeaassee help

 

[tutor_joel]

use the quadratic formula here with

a = 1
b = 2k +1
c = k^2 + k + 1

and you will see that it makes sense. Let me know if if does.

 

[maths_arghh234]

hey ... i didn't realise someone replied until now .. .. i completely forgot about finding an A, B and C ... and completing the square ... thanks

 

[swaroop]

Hi,
Now in an equation of the form ax^2+bx+c=0, the roots are given as
x=(-b+-sqrt(b^2-4ac))/2
Now if the equation gven above
a=1, b=(2k+1), c=(k^2+k+1)
If the sqrt term turns out to be negative then there are no real roots as they will go complex.
Now substitute these vaues and see what you get in the square root term. Hope this will help, if you are still unclear show steps till you have gone we can help you from there