Ihatealgebra said:
Write the equation of the line with the x-intercept (4,0) and y-intercept (0,2).
I know the x's are the 4 and the second zero which means the y's are the first zero and the 2. is the equation x=4+0 over 0+2?
I'm not exactly sure what you're saying here!!
But, you have two points on the line: (4, 0) and (0, 2)
You should be able to find the slope of this line using the fact that
slope = (y<SUB>2</SUB> - y<SUB>1</SUB>) / (x<SUB>2</SUB> - x<SUB>1</SUB>)
(x<SUB>1</SUB>, y<SUB>1</SUB>) = (4, 0)
(x<SUB>2</SUB>, y<SUB>2</SUB>) = (0, 2)
And the y-intercept for this line is where the line crosses the y-axis...isn't (0, 2) on the y-axis?
Once you know the value of m, the slope, and the y-intercept, b, you should be able to write the equation of the line in slope-intercept form,
y = mx + b